Optimal. Leaf size=358 \[ -\frac {52 b^2 \sqrt {d+c^2 d x^2}}{225 c^4}+\frac {4 a b x \sqrt {d+c^2 d x^2}}{15 c^3 \sqrt {1+c^2 x^2}}-\frac {26 b^2 \left (1+c^2 x^2\right ) \sqrt {d+c^2 d x^2}}{675 c^4}+\frac {2 b^2 \left (1+c^2 x^2\right )^2 \sqrt {d+c^2 d x^2}}{125 c^4}+\frac {4 b^2 x \sqrt {d+c^2 d x^2} \sinh ^{-1}(c x)}{15 c^3 \sqrt {1+c^2 x^2}}-\frac {2 b x^3 \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )}{45 c \sqrt {1+c^2 x^2}}-\frac {2 b c x^5 \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )}{25 \sqrt {1+c^2 x^2}}-\frac {2 \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{15 c^4}+\frac {x^2 \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{15 c^2}+\frac {1}{5} x^4 \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )^2 \]
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Rubi [A]
time = 0.35, antiderivative size = 358, normalized size of antiderivative = 1.00, number of steps
used = 14, number of rules used = 8, integrand size = 28, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.286, Rules used = {5806, 5812,
5798, 5772, 267, 5776, 272, 45} \begin {gather*} \frac {x^2 \sqrt {c^2 d x^2+d} \left (a+b \sinh ^{-1}(c x)\right )^2}{15 c^2}-\frac {2 b c x^5 \sqrt {c^2 d x^2+d} \left (a+b \sinh ^{-1}(c x)\right )}{25 \sqrt {c^2 x^2+1}}+\frac {1}{5} x^4 \sqrt {c^2 d x^2+d} \left (a+b \sinh ^{-1}(c x)\right )^2-\frac {2 b x^3 \sqrt {c^2 d x^2+d} \left (a+b \sinh ^{-1}(c x)\right )}{45 c \sqrt {c^2 x^2+1}}-\frac {2 \sqrt {c^2 d x^2+d} \left (a+b \sinh ^{-1}(c x)\right )^2}{15 c^4}+\frac {4 a b x \sqrt {c^2 d x^2+d}}{15 c^3 \sqrt {c^2 x^2+1}}+\frac {2 b^2 \left (c^2 x^2+1\right )^2 \sqrt {c^2 d x^2+d}}{125 c^4}-\frac {26 b^2 \left (c^2 x^2+1\right ) \sqrt {c^2 d x^2+d}}{675 c^4}-\frac {52 b^2 \sqrt {c^2 d x^2+d}}{225 c^4}+\frac {4 b^2 x \sqrt {c^2 d x^2+d} \sinh ^{-1}(c x)}{15 c^3 \sqrt {c^2 x^2+1}} \end {gather*}
Antiderivative was successfully verified.
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Rule 45
Rule 267
Rule 272
Rule 5772
Rule 5776
Rule 5798
Rule 5806
Rule 5812
Rubi steps
\begin {align*} \int x^3 \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )^2 \, dx &=\frac {1}{5} x^4 \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )^2+\frac {\sqrt {d+c^2 d x^2} \int \frac {x^3 \left (a+b \sinh ^{-1}(c x)\right )^2}{\sqrt {1+c^2 x^2}} \, dx}{5 \sqrt {1+c^2 x^2}}-\frac {\left (2 b c \sqrt {d+c^2 d x^2}\right ) \int x^4 \left (a+b \sinh ^{-1}(c x)\right ) \, dx}{5 \sqrt {1+c^2 x^2}}\\ &=-\frac {2 b c x^5 \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )}{25 \sqrt {1+c^2 x^2}}+\frac {x^2 \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{15 c^2}+\frac {1}{5} x^4 \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )^2-\frac {\left (2 \sqrt {d+c^2 d x^2}\right ) \int \frac {x \left (a+b \sinh ^{-1}(c x)\right )^2}{\sqrt {1+c^2 x^2}} \, dx}{15 c^2 \sqrt {1+c^2 x^2}}-\frac {\left (2 b \sqrt {d+c^2 d x^2}\right ) \int x^2 \left (a+b \sinh ^{-1}(c x)\right ) \, dx}{15 c \sqrt {1+c^2 x^2}}+\frac {\left (2 b^2 c^2 \sqrt {d+c^2 d x^2}\right ) \int \frac {x^5}{\sqrt {1+c^2 x^2}} \, dx}{25 \sqrt {1+c^2 x^2}}\\ &=-\frac {2 b x^3 \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )}{45 c \sqrt {1+c^2 x^2}}-\frac {2 b c x^5 \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )}{25 \sqrt {1+c^2 x^2}}-\frac {2 \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{15 c^4}+\frac {x^2 \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{15 c^2}+\frac {1}{5} x^4 \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )^2+\frac {\left (2 b^2 \sqrt {d+c^2 d x^2}\right ) \int \frac {x^3}{\sqrt {1+c^2 x^2}} \, dx}{45 \sqrt {1+c^2 x^2}}+\frac {\left (4 b \sqrt {d+c^2 d x^2}\right ) \int \left (a+b \sinh ^{-1}(c x)\right ) \, dx}{15 c^3 \sqrt {1+c^2 x^2}}+\frac {\left (b^2 c^2 \sqrt {d+c^2 d x^2}\right ) \text {Subst}\left (\int \frac {x^2}{\sqrt {1+c^2 x}} \, dx,x,x^2\right )}{25 \sqrt {1+c^2 x^2}}\\ &=\frac {4 a b x \sqrt {d+c^2 d x^2}}{15 c^3 \sqrt {1+c^2 x^2}}-\frac {2 b x^3 \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )}{45 c \sqrt {1+c^2 x^2}}-\frac {2 b c x^5 \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )}{25 \sqrt {1+c^2 x^2}}-\frac {2 \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{15 c^4}+\frac {x^2 \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{15 c^2}+\frac {1}{5} x^4 \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )^2+\frac {\left (b^2 \sqrt {d+c^2 d x^2}\right ) \text {Subst}\left (\int \frac {x}{\sqrt {1+c^2 x}} \, dx,x,x^2\right )}{45 \sqrt {1+c^2 x^2}}+\frac {\left (4 b^2 \sqrt {d+c^2 d x^2}\right ) \int \sinh ^{-1}(c x) \, dx}{15 c^3 \sqrt {1+c^2 x^2}}+\frac {\left (b^2 c^2 \sqrt {d+c^2 d x^2}\right ) \text {Subst}\left (\int \left (\frac {1}{c^4 \sqrt {1+c^2 x}}-\frac {2 \sqrt {1+c^2 x}}{c^4}+\frac {\left (1+c^2 x\right )^{3/2}}{c^4}\right ) \, dx,x,x^2\right )}{25 \sqrt {1+c^2 x^2}}\\ &=\frac {2 b^2 \sqrt {d+c^2 d x^2}}{25 c^4}+\frac {4 a b x \sqrt {d+c^2 d x^2}}{15 c^3 \sqrt {1+c^2 x^2}}-\frac {4 b^2 \left (1+c^2 x^2\right ) \sqrt {d+c^2 d x^2}}{75 c^4}+\frac {2 b^2 \left (1+c^2 x^2\right )^2 \sqrt {d+c^2 d x^2}}{125 c^4}+\frac {4 b^2 x \sqrt {d+c^2 d x^2} \sinh ^{-1}(c x)}{15 c^3 \sqrt {1+c^2 x^2}}-\frac {2 b x^3 \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )}{45 c \sqrt {1+c^2 x^2}}-\frac {2 b c x^5 \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )}{25 \sqrt {1+c^2 x^2}}-\frac {2 \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{15 c^4}+\frac {x^2 \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{15 c^2}+\frac {1}{5} x^4 \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )^2+\frac {\left (b^2 \sqrt {d+c^2 d x^2}\right ) \text {Subst}\left (\int \left (-\frac {1}{c^2 \sqrt {1+c^2 x}}+\frac {\sqrt {1+c^2 x}}{c^2}\right ) \, dx,x,x^2\right )}{45 \sqrt {1+c^2 x^2}}-\frac {\left (4 b^2 \sqrt {d+c^2 d x^2}\right ) \int \frac {x}{\sqrt {1+c^2 x^2}} \, dx}{15 c^2 \sqrt {1+c^2 x^2}}\\ &=-\frac {52 b^2 \sqrt {d+c^2 d x^2}}{225 c^4}+\frac {4 a b x \sqrt {d+c^2 d x^2}}{15 c^3 \sqrt {1+c^2 x^2}}-\frac {26 b^2 \left (1+c^2 x^2\right ) \sqrt {d+c^2 d x^2}}{675 c^4}+\frac {2 b^2 \left (1+c^2 x^2\right )^2 \sqrt {d+c^2 d x^2}}{125 c^4}+\frac {4 b^2 x \sqrt {d+c^2 d x^2} \sinh ^{-1}(c x)}{15 c^3 \sqrt {1+c^2 x^2}}-\frac {2 b x^3 \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )}{45 c \sqrt {1+c^2 x^2}}-\frac {2 b c x^5 \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )}{25 \sqrt {1+c^2 x^2}}-\frac {2 \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{15 c^4}+\frac {x^2 \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )^2}{15 c^2}+\frac {1}{5} x^4 \sqrt {d+c^2 d x^2} \left (a+b \sinh ^{-1}(c x)\right )^2\\ \end {align*}
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Mathematica [A]
time = 0.17, size = 222, normalized size = 0.62 \begin {gather*} \frac {\sqrt {d+c^2 d x^2} \left (225 \left (-2+3 c^2 x^2\right ) \left (a+a c^2 x^2\right )^2-30 a b c x \sqrt {1+c^2 x^2} \left (-30+5 c^2 x^2+9 c^4 x^4\right )+2 b^2 \left (-428-439 c^2 x^2+16 c^4 x^4+27 c^6 x^6\right )-30 b \left (-15 a \left (1+c^2 x^2\right )^2 \left (-2+3 c^2 x^2\right )+b c x \sqrt {1+c^2 x^2} \left (-30+5 c^2 x^2+9 c^4 x^4\right )\right ) \sinh ^{-1}(c x)+225 \left (-2+3 c^2 x^2\right ) \left (b+b c^2 x^2\right )^2 \sinh ^{-1}(c x)^2\right )}{3375 c^4 \left (1+c^2 x^2\right )} \end {gather*}
Antiderivative was successfully verified.
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Maple [B] Leaf count of result is larger than twice the leaf count of optimal. \(1161\) vs.
\(2(310)=620\).
time = 2.33, size = 1162, normalized size = 3.25
method | result | size |
default | \(\text {Expression too large to display}\) | \(1162\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.35, size = 302, normalized size = 0.84 \begin {gather*} \frac {1}{15} \, b^{2} {\left (\frac {3 \, {\left (c^{2} d x^{2} + d\right )}^{\frac {3}{2}} x^{2}}{c^{2} d} - \frac {2 \, {\left (c^{2} d x^{2} + d\right )}^{\frac {3}{2}}}{c^{4} d}\right )} \operatorname {arsinh}\left (c x\right )^{2} + \frac {2}{15} \, a b {\left (\frac {3 \, {\left (c^{2} d x^{2} + d\right )}^{\frac {3}{2}} x^{2}}{c^{2} d} - \frac {2 \, {\left (c^{2} d x^{2} + d\right )}^{\frac {3}{2}}}{c^{4} d}\right )} \operatorname {arsinh}\left (c x\right ) + \frac {1}{15} \, a^{2} {\left (\frac {3 \, {\left (c^{2} d x^{2} + d\right )}^{\frac {3}{2}} x^{2}}{c^{2} d} - \frac {2 \, {\left (c^{2} d x^{2} + d\right )}^{\frac {3}{2}}}{c^{4} d}\right )} + \frac {2}{3375} \, b^{2} {\left (\frac {27 \, \sqrt {c^{2} x^{2} + 1} c^{2} \sqrt {d} x^{4} - 11 \, \sqrt {c^{2} x^{2} + 1} \sqrt {d} x^{2} - \frac {428 \, \sqrt {c^{2} x^{2} + 1} \sqrt {d}}{c^{2}}}{c^{2}} - \frac {15 \, {\left (9 \, c^{4} \sqrt {d} x^{5} + 5 \, c^{2} \sqrt {d} x^{3} - 30 \, \sqrt {d} x\right )} \operatorname {arsinh}\left (c x\right )}{c^{3}}\right )} - \frac {2 \, {\left (9 \, c^{4} \sqrt {d} x^{5} + 5 \, c^{2} \sqrt {d} x^{3} - 30 \, \sqrt {d} x\right )} a b}{225 \, c^{3}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.39, size = 316, normalized size = 0.88 \begin {gather*} \frac {225 \, {\left (3 \, b^{2} c^{6} x^{6} + 4 \, b^{2} c^{4} x^{4} - b^{2} c^{2} x^{2} - 2 \, b^{2}\right )} \sqrt {c^{2} d x^{2} + d} \log \left (c x + \sqrt {c^{2} x^{2} + 1}\right )^{2} + 30 \, {\left (45 \, a b c^{6} x^{6} + 60 \, a b c^{4} x^{4} - 15 \, a b c^{2} x^{2} - 30 \, a b - {\left (9 \, b^{2} c^{5} x^{5} + 5 \, b^{2} c^{3} x^{3} - 30 \, b^{2} c x\right )} \sqrt {c^{2} x^{2} + 1}\right )} \sqrt {c^{2} d x^{2} + d} \log \left (c x + \sqrt {c^{2} x^{2} + 1}\right ) + {\left (27 \, {\left (25 \, a^{2} + 2 \, b^{2}\right )} c^{6} x^{6} + 4 \, {\left (225 \, a^{2} + 8 \, b^{2}\right )} c^{4} x^{4} - {\left (225 \, a^{2} + 878 \, b^{2}\right )} c^{2} x^{2} - 450 \, a^{2} - 856 \, b^{2} - 30 \, {\left (9 \, a b c^{5} x^{5} + 5 \, a b c^{3} x^{3} - 30 \, a b c x\right )} \sqrt {c^{2} x^{2} + 1}\right )} \sqrt {c^{2} d x^{2} + d}}{3375 \, {\left (c^{6} x^{2} + c^{4}\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int x^{3} \sqrt {d \left (c^{2} x^{2} + 1\right )} \left (a + b \operatorname {asinh}{\left (c x \right )}\right )^{2}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: TypeError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int x^3\,{\left (a+b\,\mathrm {asinh}\left (c\,x\right )\right )}^2\,\sqrt {d\,c^2\,x^2+d} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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